A ball of mass 0.20 kg hits a wall at an angle of `45^(@)` with a velocity of 25 m/s if the ball rebound at `90^(@)` to the direction of incidence calculate the change in momentum of the ball.

Explanation

Change is momentum `= (-mv cos 45^(@))`
`-(mv cos 45^(@))`
dp= 2mv `cos 45^(@) `
`|vec(dp)| = 2xx 0.2xx 25 xx (1)/(sqrt(2))`
`:. Dp = 5 sqrt(2) Ns`