A neutron having a mass `1.67 xx10^(-27)` kg and moving at `10^(8) ms^(-1)` collides with a deuteron at rest and sticks to it if the mass of deuteron is `3.34 xx10^(-27)` kg find the speed of the combination

Explanation

For neutron :
`m_(1) = 1.67 xx 10^(27) kg`
`u_(1) = 10^(8) ms^(-1)`
For deuteron:
`m_(2) = 3.34 xx 10^(27) kg u_(2) = 0`
Let v be the speed of the combination
Then by conservation of momentum
`m_(1)u_(1) + m_(2) u_(2) = (m_(1) + m_(2)) v`
`1.67 xx 10^(27) xx 10^(8) + 3.34 xx 10^(27)`
`=(1.67 +3.34 ) xx 10^(-27) xx v`
Speed of the combination
`v=(1.67 xx 10^(-27) xx 10^(8))/( 5.01 xx 10^(-27))`
`=0.333 xx 10^(8) ms^(-1)`