A ball of mass 1 kg hangs in equlibrium from two stings OA and OB in the diagram calcualte the tensions in stings OA and OB take `g=10ms^(-2)`

Explanation

Given mass of the ball
`=1kg`
`g=10 ms^(-1)`
Various forces acting at the point O are at shown in the diagram .The three forces are in equilibrium .using Lamis theorem
`(T_(1))/(sin150^(@)) = (T_(2))/(sin 120^(@)) = (10)/(sin 90^(@))`
and `T_(1) 10 sin 30^(@) = 10 xx 0.5 =5N`
and `T_(2) =10 sin 60^(@) =10 xx (sqrt(3))/(2)`
`=5sqrt(3) N`