Determine the maximum acceleration of the train in which a box lying on its floor will remain stationary given that the coefficeient of static friction between the box and the train 's floor is 0.15 take `g=10ms^(-2)`

Explanation

As the acceleration of the bos ix due to static friction so
ma `=f le mu_(s) R = mu_(3) mg`
`:. ,a = mu_(s) g`
or `a_(max) =mu_(s) g = 0 .15 xx 10 = 1.5 ms^(-2)`