A ball of mass 1 kg and another of mass 2 kg are dropped from a tall building whose height is 80 m. After, a fall of 40 m each towards Earth, their respective kinetic energies will be in the ratio of

Options

A. `sqrt(2):1`
B. `1:sqrt(2)`
C. `2:1`
D. `1:2`

Answer

D

Explanation

Here `u=0`
`(Ek_(1))/(Ek_(2))=((1)/(2)m_(1)v_(1)^(2))/((1)/(2)m_(2)v_(2)^(2))`
`V_(1)=V_(2)` after 40 m
`(Ek_(1))/(Ek_(2))=(m_(1))/(m_(2))=(1)/(2)`