A body of mass 5 kg initially at rest is subjected to a force of 20N. What is the kinetic energy acquired by the body at the end of 10s?

Explanation

`m=5kg, u=0, F=20N`
`t=10s,(1)/(2)mv^(2)=?`
Formula: `a=(F)/(m)=(20)/(5)=4ms^(-2)`
`v=u+at=0+4xx10=40ms^(-1)`
`KE=(1)/(2)xx5xx(40)^(2)=4000` Joule