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A body of mass 0.3 kg is tken up an incl...

A body of mass 0.3 kg is tken up an inclined plane of length to m and height 5 m and then allowed to slide down to bottom again. Find
kinetic energy at the end of the trip.

Text Solution

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`sintheta=(5)/(10)=(1)/(2)=sin.(pi)/(6)` so, `theta=(pi)/(6)`
P.E at top = `0.3xx9.8xx5=14.7J`
`{:("K.E at the end"),(" of trip"):}}={{:("P.E at top"),("- Work done"),("against friction"):}`
`K.E=14.7-7.6`
`=7.1J`
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