What is the stopping distance for a vehicle of mass m moving with speed v along a level road, if the co-efficient of friction between the tyres and the road is `mu`?

Explanation

When the vehicle of mass m is moving with velocity v, the kinetic energy of the vehicle `KE=((1)/(2))mv^(2)` and if s is the stopping distance, then work done by friction.
`W=fscostheta=mumgscos180^(@)`
So by work - Energy theorem,
`W=Deltak=k_(f)-k_(i)`
i.e., `-mumgs=0-(1)/(2)mv^(2)ors=(v^(2))/(2mug)`