A vehicle of mass 15 quintal climbs up a hill 200m high. It then moves on a level road with speed of `30ms^(-1)`. Calculate the potential energy gained by it and its total mechanical energy while running on the top of the hill.

Explanation

m = 15 quintal = 1500 kg,
`g=9.8ms^(-2),h=200m`
P.E gained `u=mgh`
`=1500xx9.8xx200`
`=2.94xx10^(6)J`
When the vehicle runs on a level road with speed of `30ms^(-1)`, its K.E is
`K=(1)/(2)mv^(2)=(1)/(2)xx1500xx(30)^(2)`
`=0.675xx10^(6)J`
Total mechanical energy,
`E=K+U`
`=(0.675+2.94)xx10^(6)`
`=3.615xx10^(6)J`