If the KE of a body increases by 300% by what percent will the linear momentum of the body increase.

Explanation

`KE=(1)/(2)mv^(2)=(p^(2))/(2m)`
`therefore` Initial momentum
`p=sqrt(2mKE)`
`{:("Increase"),("in KE"):}}=300%" of KE"`
= 3 KE
`{:("Final"),("KE (KE')"):}}=KE+3KE=4KE`
`{:("Final"),("momentum"):}}p'=sqrt(2mKE')=sqrt(2m(4KE))`
`=2sqrt(2mKE)implies2p`
`{:("Increase in"),("momentum"):}}=(p'-p)/(p)xx100`
`=(2p-p)/(p)xx100=(p)/(p)xx100`
% increase in momentum = 100%