The height at which the acceleration due to gravity becomes `(g)/(9)` (where g = the acceleration due to gravity on the surface of the Earth) in terms of R, the radius of the Earth, is:

Options

A. 2R
B. `(R)/(2)`
C. `sqrt(2)R`
D. `(R)/(sqrt2)`

Answer

A

Explanation

The acceleration due to gravity at a height h from the ground is given as `(g)/(9)`.

`(GM)/(r^2)=(GM)/(R^2).(1)/(9)`
The height above the ground is 2R.