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The reading of a spring balance correspo...

The reading of a spring balance corresponds to 100 N while situated at the North pole and a body is kept on it. The weight recorded on the same scale if it is shifted to the equator (take, `g=10m//s^(2)` and radius of the Earth `R=6.4xx10^(6)m`) is:

A

99.66 N

B

110 N

C

97.66 N

D

106 N

Text Solution

Verified by Experts

The correct Answer is:
A

`g_(p)-g_(e)=Romega^(2)=3.37xx10^(-2)ms^(-2)`
`g_(e)=g_(p)-3.37xx10^(-2)ms^(-2)`
`=(10-0.0337)ms^(-2)`
`=9.9663ms^(-2)`
`W_(e)=mg_(e)=(100)/(10)xx9.9663N`
`=99.663N`
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