For a satellite moving in an orbit around the earth, the ratio of kinetic energy of potential

Options

A. `1:sqrt(2)`
B. `1:2`
C. `2:1`
D. `sqrt(2):1`

Answer

B

Explanation

Kinetic energy
`K.E=(1)/(2)mv^(2)`
`K.E=(1)/(2)m(sqrt((GM)/(r)))^(2)=(GMm)/(2r)`
Magnitude of potential energy
`P.E=(GMm)/(r)`
`therefore(K.E)/(P.E)=(GMm)/(2r)xx(r)/(GMm)=(1)/(2)`
`thereforeK.E=P.E=1:2`