There are two wires of same material and same length while the diameter of second wire is two times the diameter of first wire, then the ratio of extension produced in the wire by applying same load will be:

Options

A. `2:1`
B. `1:2`
C. `1:1`
D. `4:1`

Answer

D

Explanation

Extension,
`Deltal=(F)/(A).(l)/(Y)=(F)/(pir^2).(l)/(Y)`
For the two wires, F, l and Y are same.
So, `(Deltal_1)/(Deltal_2)=(r_(2)^(2))/(r_(1)^(2))=((2)/(1))^(2)`
`=4:1`