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Two wires of diameter 0.25 cm, one made ...

Two wires of diameter 0.25 cm, one made of steel and the other made of brass are loaded as shown in Fig. 9.13. The unloaded length of steel wire is 1.5 m and that of brass wire is 1.0 m. Compute the elongations of the steel and the brass wires.

A

`1.1xx10^(-4)m`

B

`1.8xx10^(-4)m`

C

`1.3xx10^(-4)m`

D

`1.5xx10^(-4)m`

Text Solution

Verified by Experts

The correct Answer is:
C
`Y=(F.l)/(A.Deltal),Deltal=(F.l)/(A.Y)`
For Brass,
`Deltal=(6xx9.8Nxx1m)/(pi(0.125xx10^(-2)m)^(2)xx(9.1xx10^(10)Nm^(-2)))`
`=1.3xx10^(-4)m`
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