A square lead slab of side 50 cm and thickness 10.0 cm is subjected to a shearing force (on its narrow face) of magnitude `9.0xx10^(4)N`. The lower edge is riveted to the floor. How much is the upper edge displaced, if the shear modulus of lead is `5.6xx10^(9)` Pa?

Explanation

Here `L=50cm=50xx10^(-2)m,G=5.6xx10^(9)Pa,F=9.0xx10^(4)N`.
Area of the face on which force is applied,
`A=50xx10=500sq.cm=0.05m^(2)`
If `DeltaL` is the displacement of the upper edge of the slab due to tangential force F applied, then
`G=(F//A)/(DeltaL//L)`
(or) `DeltaL=(FL)/(GA)`
`=(9xx10^(4)xx50xx10^(-2))/(5.6xx10^(9)xx0.05)=1.6xx10^(-4)m`