The neck and bottom of a bottle are 2 cm and 10 cm in diameter respectively. If the cork is pressed with a force of 1.2 kg f in the neck of the bottle, calculate the force exerted on the bottom of the bottle.

Explanation

Here `2r=2cm"(or)"r=1cmand 2R=10cm"(or)"R=5cm`
`a=pir^(2)andA=piR^(2)`
`f=1.2kg`
`f=1.2xx9.8N`
`{:("Force on"),("the bottom"):}}F=(f)/(a)xxA=(1.2xx9.8)/(pir^2)xxpiR^(2)`
`=1.2xx9.8xx(R^2)/(r^2)`
`=1.2xx9.8xx(25)/(1)N`
`=1.2xx25kgf=30kgf`