A liquid flows throug ha pipe of 1.0 mm radius and 10 cm length under a pressure `10^(4)` dyne `cm^(-2)`. Calculate the rate of flow and the speed of the liquid coming out of the tube. The coefficient of viscosity of the liquid is 1.25 centipoise.

Explanation

Here `r=1.0mm=0.1cm,l=10cm`
`P=10^(4)` dyne `cm^(-2)`,
`eta=1.25` centipoise `=0.0125` poise.
Rate of flow, `Q=(piPr^4)/(8etal)=(3.142xx10^(4)xx(0.1)^(4))/(8xx0.0125xx10)`
`=3.142cm^(3)s^(-1)`
Speed of liquid,
`V=(Q)/("cross sectional area")`
`=(3.142)/(pir^2)=(1)/(r^2)=(1)/((0.1)^(2))`
`=100cms^(-1)`
`=1ms^(-1)`