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Cos 2B =(cos ( A+C )) / cos( A-C) => tan...

`Cos 2B =(cos ( A+C )) / cos( A-C) => tan A, tan B, tan C` are in

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(cos (AB)) / (cos (A + B)) + (cos (C + D)) / (cos (CD)) = 0rArr tan A tan B tan C tan D =