`A+C=2B=>(cosC-cosA)/(sinA-sinC)=`

A+C=2B then (cosC-cosA)/(sinA-sinC)=

If A+C=2B, then (cosC-cosA)/(sinA-sinC)=

If A+C=2B, then (cosC-cosA)/(sinA-sinC)=

In triangle ABC , right angled at B, if tanA =1/2 , then the value of (sinA(cosC + cosA))/(cosC(sinC - sinA)) is: triangle ABC में B एक समकोण है यदि tanA =1/2 तो (sinA(cosC + cosA)) /(cosC(sinC - sinA)) का मान क्या होगा ?

In triangleABC, a(sinB-sinC)+b(sinC-sinA)+c(sinA-sinB)=

If A+B+C=pi , prove that : (cosA)/(sinBsinC) + (cosB)/(sinC sinA) + (cosC)/(sinA sinB) =2 .

If A+B+C=pi , prove that (cosA)/(sin B sinC)+(cos B)/(sin C sinA)+(cos C)/(sin A sinB)=2 .

If A+B+C=pi , prove that : (cosA)/(sinb sinC) + (cosB)/(sinC sin) + (cosC)/(sinA sinB) =2 .

If A+B+C=pi , prove that : (cosA)/(sinb sinC) + (cosB)/(sinC sin) + (cosC)/(sinA sinB) =2 .