`(sin 7theta + 6 sin 5theta + 17 sin 3theta + 12 sin theta) / (sin6 theta + 5 sin4theta +12 sin2theta)`

(sin7 theta+6sin5 theta+17sin3 theta+12sin theta)/(sin6 theta+5sin4 theta+12sin2 theta)=

(sin7 theta+6sin5 theta+17sin3 theta+12sin theta)/(sin6 theta+5sin4 theta+12sin2 theta)=

sin theta + sin3 theta + sin5 theta = 0

sin 4 theta + 2 sin 8 theta + sin 12 theta = ?

( sin 2 theta + 2 sin 4 theta + sin 6 theta )/(sin 4 theta + 2 sin 6 theta + sin 8 theta ) =

(sin7theta+6sin5theta+17sin3theta+12sintheta)/(sin6theta+5sin4theta+12sin2theta) is equal to

(sin7theta+6sin5theta+17sin3theta+12sintheta)/(sin6theta+5sin4theta+12sin2theta) is equal to

Prove that : (sin theta + 2 sin 3theta + sin 5theta)/(sin 3theta + 2 sin 5theta + sin 7theta) = (sin 3theta)/(sin 5theta)

If sin 6theta = sin 4theta - sin 2theta , then theta =