Let `K_(1)` be the maximum kinetic energy of photoelectrons emitted by a light of wavelength `lambda_(1)` and `K_(2)` corresponding to `lambda_(`2). If `lambda_(1) = 2lambda_(2)`, then

Let be the maximum kinetic energy of photoelectrons emitted by light of wavelength lambda_(1) and lambda_(2) correspondingto wavelength lambda_(2) . If lambda_(1) = 2lambda_(2) then:

If K_(1) and K_(2) are maximum kinetic energies of photoelectrons emitted when light of wavelength lambda_(1) and lambda_(2) respectively are incident on a metallic surface. If lambda_(1)=3lambda_(2) then

If K_(1) and K_(2) are maximum kinetic energies of photoelectrons emitted when light of wavelength lambda_(1) and lambda_(2) respectively are incident on a metallic surface. If lambda_(1)=3lambda_(2) then

If K_(1) and K_(2) are maximum kinetic energies of photoelectrons emitted when light of wavelength lambda_(2) and lambda_(1) respectively are incident on a metallic surface. If lambda_(1)=3lambda_(2) then

If K_(1) and K_(2) are maximum K.E. photoelectron emitted when lights wavelength lambda_(1) and lambda_(2) respectively incident a metallic surface .If lambda_(1)=3lambda_(2) ,then…..

The maximum kinetic energies of photoelectrons emitted from a metal are k_(1) and k_(2) when it is irradiated with light of wavelenght lambda_(1) and lambda_(2) respectively. Find work function of the metal.