The molar conductivity of a 1.5 M solution of an electrolyte is found to be `138.9 S cm^(2) mol^(-1)` . Calculate the conductivity of this solution.

Define the following : (i) Molar conductivity (ii) Fuel cell (b) The molar conductivity of a 1.5 M solution of an electrolyte is found to be 138.9" S Cm"^(2)"mol"^(-1) . Calculate the conductivity of the solution.

The molar conductivity of 1.5 M solution of an electrolysis is found to be 138.9 S cm^2 mol^-1 . Calculate the conductivity of this solution?

molar conductance of 1.5 M solution of an electrolyte is 138.9 S cm^(2) Mol^(-1) . Find the specific conductance.

The molar conductance of a 0.1 M solution of an electrolyte was found to be 400 ohm^(-1) cm^(2) "mol"^(-1) . The cell constant of the cell is 0.1cm^(-1) . The resistance of the solution is :

The resistance of a 0.5 M solution of an electrolyte in a conductivity 'cell was found to be 25 ohm. Calculate the molar conductivity of the solution, if the electrodes in the cell are 1.6 cm apart and have an area of 3*2cm^(2) .

The resistance of a conductivity cell when filled with 0.05M solution of an electrolyte x is 100 Omega at 40^(@)C . The same conductivity cell filled with 0.01M solution of electrolyte y has a resistance of 50 Omega . The conductivity of 0.05 M solution of electrolyte x is 1.0 xx 10^(-4) S cm^(-1) . Calculate (i) cell constant (ii) conductivity of 0.01 M solution (iii) molar conductivity of 0.01 M solution

The resistance of a 0.5M solution of an electrolyte was found to be 30Omega . Calculate the molar conductivity of the solution if the electrods in the cell are 1.5 cm a part and having an area of cross section is 2.0 cm^(2) .

The resistance of 0.25 M solution of an electrolyte was found to be 75 Omega . Calculate molar conductivity of the solution, if the electrodes in the cell are 1.8 cm apart and have an area of cross section 3.6 cm^2 .