`(1-tan^2 3 0^(@))/(1+tan^2 3 0^(@))=`

(2tan3 0^(@))/(1-tan^2 3 0^(@))

(2tan3 0^(@))/(1-tan^2 3 0^(@))

The value of (tan 70^(@) - tan 20^(@))/( tan 50^(@))= .............. A) 1 B) 2 C) 3 D) 0

(1 - tan^2 45^0)/(1 + tan^2 45^0)

S o l v e(sin1 0^(@))^(tanx+tan3x)=tan1 5^(@)+tan3 0^(@)+tan1 5^(@)tan3 0^(@), x in (0,pi]

(tan4A+tan2A)(1-tan^(2)3A tan^(2)A)=2tan3A sec^(2)A

If (1+tan 1^@) (1+tan 2^@) (1 + tan 3^@)...... (1+tan 44^@) (1 + tan 45^@)=N, then find the number of digits in N. (Here log_10 2= 0.301).

(1-tan^(2)45)(1+tan^(2)45)= a) tan90^0 b)1 c) sin45^0 d)0

(1+tan1^(0))(1+tan2^(0))(1+tan3^(0)).......(1+tan45^(0)) =?

Prove that (1+tan1^(0))(1+tan2^(0))......(1+tan45^(@))=2^(23)