A block A is kept on a rough inclined plane. Initially `theta = 0`. The co-efficient of kinetic friction between A and the inclined plane is `sqrt(3)` The angle `theta` is increased slowly. When `theta` becomes `60^(@)`, then :

An ice cube is kept on an inclined plane of angle 30^(@) . The coefficient to kinetic friction between the block and incline plane is 1//sqrt(3) . What is the acceleration of the block ?

An ice cube is kept on an inclined plane of angle 30^(@) . The coefficient to kinetic friction between the block and incline plane is the 1//sqrt(3) . What is the acceleration of the block ?

[ A block A of mass m is ],[ kept on a rough inclined ],[ plane of inclination theta .The ],[ coefficient of static ],[ friction between the block ],[ and the surface is mu_(s)=],[0.75 .If the angle theta is ],[ slowly increased from 0^(@)],[ to 37^(@) ,then the friction ],[ versus theta graph is ]

A block of mass m is at rest on a rough inclined plane of angle of inclination theta . If coefficient of friction between the block and the inclined plane is mu , then the minimum value of force along the plane required to move the block on the plane is

A block of mass m is at rest on a rough inclined plane of angle of inclination theta . If coefficient of friction between the block and the inclined plane is mu , then the minimum value of force along the plane required to move the block on the plane is

A block of mass m moves with constant speed down the inclined plane of inclination theta . Find the coefficient of kinetic friction.

A block of mass m moves with constant speed down the inclined plane of inclination theta . Find the coefficient of kinetic friction.

A solid cylinder is rolling down a rough inclined plane of inclination theta . Then

A solid cylinder is rolling down a rough inclined plane of inclination theta . Then

[" A block "A" of mass "m" is kept "],[" on a rough inclined plane of "],[" inclination "theta" .The coefficient "],[" of static friction between the "],[" block and the surface is "mu_(s)],[=0.75" .If the angle "theta" is "],[" slowly increased from "0^(@)" to "],[37^(@)" ,then the friction versus "theta],[" graph is "]