If `(x^2+y^2)dy=xydx` and `y(1)=1`. If `y(x_0)=e` then `x_0` is equal to (A) `sqrt(2)e` (B) `sqrt(3)e` (C) `2e` (D) `e`

If (x^2+y^2)dy=xydx and y(1)=1 and y(x_o)=e , then x_o=

If (x^(2)+y^(2))dy=xydx and y(1)=1 and y(x_(o))=e, then x_(o)=

Let y(x) is the solution of differential equation x(dy)/(dx)+y=x log_ex and 2y(2)=log_e 4-1 . Then y(e) is equal to (A) e^2 /2 (B) e/2 (C) e/4 (D) e^2/4

(x^(2)+y^(2))dy=xydx . It is given that y(1)=1 and y(x_(0))=e . Find the vale of x_(0) .

If x^3dy+ xydx= 2ydx +x^2dy and y(2) =e then y(4) = ?

If x^(3)dy+xydx=x^(2)dy+2ydx,y(2)=e then y(-1)=

If x^(3)dy+xydx=x^(2)dy+2ydx,y(2)=e then y(-1)=

If ln((e-1)e^(xy)+x^(2))=x^(2)+y^(2) then ((dy)/(dx))_(1,0) is equal to

Let y(x) is the solution of differential equation (dy)/(dx)+y=x log x and 2y(2)=log_(e)4-1 Then y(e) is equal to (A) (e^(2))/(2) (B) (e)/(2)(C)(e)/(4)(D)(e^(2))/(4)

If x=e^(y+e^(y+e^y^(------ ∞))) , x>0 , then (dy)/(dx) is equal to (A) (x)/(1+x) (B) (1)/(x) (C) (1-x)/(x) (D) (1+x)/(x)