" If "x sqrt(1+y)+y sqrt(1+x)=0" and "x!=y" then "(dy)/(dx)=

If x sqrt(1+y)+y sqrt(1+x)=0 and x!=y ,then (1+x)^(2)(dy)/(dx)+(3)/(2)=

If x sqrt(y+1)+y sqrt(x+1)=0 & x!=y, then (dy)/(dx)=

If x sqrt (y+1) + y sqrt (x+1) =0 and x != y then dy/dx=............ A) frac{1}{(1+x)^2} B) - frac{1}{(1+x)^2} C) (1+x)^2 D) - frac{x}{x+1}

If x sqrt ( 1+ y) + y sqrt( 1+x) =0 , prove that (dy)/( dx) = - (1)/( (1+x)^2) .

If x sqrt(1+y)+y sqrt(1+x)=0, then prove that (dy)/(dx)=-(1+x)^(-2)

If (x)/(sqrt( 1+x)) +(y)/( sqrt(1+y))=0and x ne y ,then (dy)/(dx)=

If x sqrt(1+y)+y sqrt(1+x)=0 then the value of (dy)/(dx) is -

If x sqrt(1+y)+y sqrt(1+x)=0, prove that (dy)/(dx)=-(1)/((x+1)^(2))