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Match matrix (E(Ag^(+)//Ag)^(@)=0.8K(sp)...

Match matrix `(E_(Ag^(+)//Ag)^(@)=0.8K_(sp)(AgCl)=10^(-10))`

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If 6.65xx10^(-2)g of metalllic zinc is added to 100ml saturated solution of AgCl , it react with Ag^(+) of solution as following reaction. Zn(s)+2Ag^(+)(aq)hArrZn^(2+)(aq)+2Ag(s) and approximately 10^(-x) moles of Ag will be precipated. Calculate the value of x (Given E_(Zn^(++)//Zn)^(@)=-0.76VE_(Ag^(+)//Ag)^(@)=0.8V, K_(sp) of AgCl=10^(-10) , atomic mass of Zn=65.3u, 10^(52.8813)=7.61xx10^(52) )

If 6.65xx10^(-2)g of metalllic zinc is added to 100ml saturated solution of AgCl , it react with Ag^(+) of solution as following reaction. Zn(s)+2Ag^(+)(aq)hArrZn^(2+)(aq)+2Ag(s) and approximately 10^(-x) moles of Ag will be precipated. Calculate the value of x (Given E_(Zn^(++)//Zn)^(@)=-0.76VE_(Ag^(+)//Ag)^(@)=0.8V, K_(sp) of AgCl=10^(-10) , atomic mass of Zn=65.3u, 10^(52.8813)=7.61xx10^(52) )

What would be the electrode potential of a silver electrode dipped in a saturated solution of AgCl in contact with 0.1 M KCl solution at 25^(@)C ? E^(c-)._(Ag^(o+)|Ag)=0.799 V K_(sp) of AgCl=1xx10^(-10)

What would be the electrode potential of a silver electrode dipped in a saturated solution of AgCl in contact with 0.1 M KCl solution at 25^(@)C ? E^(c-)._(Ag^(o+)|Ag)=0.799 V K_(sp) of AgCl=1xx10^(-10)

What would be the electrode potential of a silver electrode dipped in a saturated solution of AgCl in contact with 0.1 M KCl solution at 25^(@)C ? E^(c-)._(Ag^(o+)|Ag)=0.799 V K_(sp) of AgCl=1xx10^(-10)

The standard reduction potential E_(Ag+//Ag)^(@)= 0.80V at 298K. If K_(sp)=1.56*10^-10 for AgCI, calculate the standard half cell reduction potential for the Ag/AgCI electrode.

The following cell is set up at 25^@C, Ag(s)|Ag^(+)||Cl^(-)||AgCl(s)|Ag(s) Given that E_(Ag^(+)//Ag)^(0)=0.7999V and E_(AgCl//Ag_((s))//Cl^(-)) 0.22 volt, the solubility product of AgCl is

The following cell is set up at 25^@C, Ag(s)|Ag^(+)||Cl^(-)||AgCl(s)|Ag(s) Given that E_(Ag^(+)//Ag)^(0)=-0.7999V and E_(AgCl//Ag_((s))//Cl^(-))= 0.22 volt, the solubility product of AgCl is

A half cell reaction Ag_(2)S(s)+2e^(-) rarr 3Ag(s)+S^(2-) is carried out in a half cell Pt_(Ag_(2)S|Ag,H_(2)S(0.1M)), at [H^(o+)]=10^(-3), The EMF of the half cell is [E^(c-)._(Ag^(o+)|Ag)=0.80V,K_(a(H_(2)S))=10^(-21), and K_(sp) of Ag_(2)S=10^(-49)]