" minimen "2.8+3y" who "xy=6

If the area of the triangle formed by the pair of lines 8x^(2)-6xy+y^(2)=0 and the line 2x+3y=a is 7 then a=

If the area of the triangle formed by the pair of lines 8x^(2)-6xy+y^(2)=0 and the line 2x+3y=a is 7 then a=

If the area of the triangle formed by the pair of lines 8x^2 - 6xy + y^2 = 0 and the line 2x+3y=a is 7 then a=

" If "x^(3)+y^(3)+6xy=8" .Then "|x+y|" is equal to "(x,y in N)

x+2/y=6/3 and y+2/x=3 then xy=

Divide: (i) 5m^(2) - 30 m^(2) + 45m by 5m (ii) 8x^(2) y^(2) - 6xy + 10 x^(2) y^(3) by 2xy (iii) 9x^(2) y - 6xy + 12 xy^(2) by - 3xy (iv) 12x^(4) + 8x^(3) - 6x^(2) by -2x^(2)

Subtract : 7xy + 5x^(2) - 7y^(2) + 3 " from " 7x^(2) - 8xy + 3y^(2) - 5

Simplify the following : 2x^(2) + 3y^(2) - 5xy +5x^(2) - y^(2) + 6xy - 3x^(2)