At `25^(@)C`, a conductivity cell was filled with `0.1 M NalL` solution. The conductivity of this solution is `9.2 xx 10^(3) s cm^(-1)` and resistance is `176.6 ohm`. The cross-sectional is `176.6 ohm`. What must have been the distance between the electrodes ?

A conductance cell was filled with a 0.02 M KCl solution which has a specific conductance of 2.768xx10^(-3)ohm^(-1)cm^(-1) . If its resistance is 82.4 ohm at 25^(@) C the cell constant is:

A conductance cell was filled with a 0.02 M KCl solution which has a specific conductance of 2.768xx10^(-3)ohm^(-1)cm^(-1) . If its resistance is 82.4 ohm at 25^(@) C the cell constant is:

A conductance cell was filled with a 0.02 M KCl solution which has a specific conductance of 2.768xx10^(-3)ohm^(-1)cm^(-1) . If its resistance is 82.4 ohm at 25^(@) C the cell constant is:

The conductivity of 0*2M " KCl solution is " 3 Xx 10^(-2) ohm^(-1) cm^(-1) . Calculate its molar conductance.

For mercury at 0^(@)C specific conductance. k = 1.062963 xx 10^(6) S//m (a) If the resistance of a cell containing mercury is 0.243166 ohm, what is the cell constant of the cell ? (b) If the same cell is filled with KCl solution at 0^(@)C , the resistance of the cell is 3.966 xx 10^(4) ohm. What is the conductivity of KCl solution ? (c) If the average cross-sectional area of the cell is 0.9643 mm^(2) , what is the effective distance between the electrodes ?

Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1M is 100ohm. The conductivity of this solution is 1.29 S m^(-1) . Resistance of the same cell when filled with 0.2M of the same solution is 520ohm. The molar conductivity of 0.02M solution of the electrolyte will be

At a definite temperature, a conductivity cell is filled with 0.02 (N) KCl solution, the resistance is 380 ohm. If the specific conductance of 0.02(N) KCl solution at the same temperature be "0.002758 ohm.cm"^(-1) . Find the cell constant. If the distance between the electrodes is 0.80 cm, what is the average area of the electrodes?