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int^(pi/2)log(sin x)dx=...

int^(pi/2)log(sin x)dx=

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int_(0)^((pi)/(2))log(sin x)dx

If I_(1)=int_(0)^(pi//2)log (sin x)dx and I_(2)=int_(0)^(pi//2)log (sin 2x)dx , then

Show that int_(0)^(pi//2) log (sin x) dx = - pi/2 log 2

Evaluate the following definite integrals: \int_{0}^((pi)/2) log(sin x) dx

Prove that: int_(0)^(pi//2) log (sin x) dx =int_(0)^(pi//2) log (cos x) dx =(-pi)/(2) log 2

Prove that: int_(0)^(pi//2) log (sin x) dx =int_(0)^(pi//2) log (cos x) dx =(-pi)/(2) log 2

Evaluate : int_0^(pi/2) log sin x dx .

int_(0)^(pi//2) log sin x dx =

int_(0)^((pi)/(2))log(sin2x)dx