A particle is projected from earth surface with a velocity `sqrt((4gR)/(3))` in upward direction where R is the radius of earth. Find the velocity of particle when it is at half its maximum height.

A particle is projected vertically upwards with a velocity sqrt(gR) , where R denotes the radius of the earth and g the acceleration due to gravity on the surface of the earth. Then the maximum height ascended by the particle is

A particle is projected vertically upwards with a velocity sqrt(gR) , where R denotes the radius of the earth and g the acceleration due to gravity on the surface of the earth. Then the maximum height ascended by the particle is

A particle is projected vertically upwards with a velocity sqrt(gR) , where R denotes the radius of the earth and g the acceleration due to gravity on the surface of the earth. Then the maximum height ascended by the particle is

Two particles are projected from the surface of the earth with velocities sqrt(5/7gR) and sqrt(2/5gR) where, R is the radius of the earth what should be the ratio of maximum heights attained?

A particle is projected vertically up with velocity v=sqrt((4gR_e)/3) from earth surface.The velocity of particle at height equal to half of the maximum height reached by it

If a body is to be projected vertically upwards from earth's surface to reach a height of 10R where R is the radius of earth. The velocity required to be si is