For a cell, the terminal potential difference is `2.2 V`, when circuit is open and reduces to `1.8 V `. When cell is connected to a resistance `R=5Omega`, the internal resistance of cell `(R)` is

For a cell terminal potential difference is 2.2 V when circuit is open and reduces to 1.8V when cell is connected to a resistance of R= 5Omega then determine internal resistance of cell is:-

For a cell terminal potential difference is 2.2 V when circuit is open and reduces to 1.8V when cell is connected to a resistance of R= 5Omega then determine internal resistance of cell is:-

The terminal potential difference of a cell which draws 10A current from a charger is 6.8V.If the cell has an open circuit voltage 5.6V, the internal resistance of the cell is

The terminal potential difference for a cell is 8.5 V when current is 2A and 9 V when current is 1.5A. What is the internal resistance of cell ?

The p.d. between the two terminals of a cell in open circuit is 2 volt. The p.d. falls to 1.5 volts when the cell is connected across a 2 ohm resistance. Find the internal resistance of the cell.

The emf of a cell is 2 V. When the terminals of the cell is connected to a resistance 4Omega . The potential difference across the terminals, if internal resistance of cell is 1Omega is

The potential difference between the terminals of a cell in open circuit is 2.2V. When it is connected through a resistance of 5 ohm , the P.D. falls to 1.8V. Find the internal resistance of the cell.