[y=(7+4x)/(3)],[2x+3y=-2]

2x + 3y + 1 = 0 , ( 7- 4x )/(3) = y

{:(3x + 2y = 4),(2x - 3y = 7):}

{:(3x + 2y = 4),(2x - 3y = 7):}

Solve : (7 + x)/(5) - (2x - y)/(4) = 3y - 5 (5y - 7)/(2) + (4x - 3)/(6) = 18 - 5x

If [(x,3x-y),(2x+z,3y-w)]=[(3,2),(4,7)], then find x,y,z,w.

Find the values of x, y, z and w if [(x,3x-y),(2x+z,3y-w)]=[(3,2),(4,7)]

If [(x,3x-y),(2x+z,3y-w)]=[(3,2),(4,7)], then find x+y+z+w.

Solve for x and y if [(x^(2)),(y^(2))]+2[(2x), (3y)]=3[(7),(-3)]

Add: 4xy+5x+7y, -4xy-y-3x, 3xy-3y+2x

If [2x+y,4x,5x-7 4x]=[7 7y-13 y x+6] , then the value of x+y is x=3 , y=1 (b) x=2 , y=3 (c) x=2 , y=4 (d) x=3 , y=3