It is given that `cos(theta-alpha)=a, cos(theta-beta)=b`
What is `cos(alpha-beta)` equal to ?

Consider the following for next three) items: It given that cos(theta-alpha ) = a, cos(theta-beta) = b . What is cos (alpha-beta) equal to ?

It is given that cos(theta-alpha)=a, cos(theta-beta)=b What is sin^(2)(alpha-beta)+2abcos(alpha-beta) equal to ?

If cos(theta-alpha)=a , sin(theta-beta)=b then cos^2(alpha-beta)+2 ab sin(alpha-beta) is equal to

If cos(theta - alpha)=a, cos(theta-beta)=b , then sin^(2)(alpha -beta) + 2abcos(alpha-beta)=0

s(theta-alpha)=a and cos(theta-beta)=b, then sin^(2)(alpha-beta)+2ab cos(alpha-beta)=

If sin(theta+alpha)=a and sin(theta+beta)=b then cos2(alpha-beta)-4abcos(alpha-beta) is equal to

If cos(theta-alpha)=a and cos(theta-beta)=b then the value of sin^(2)(alpha-beta)+2ab cos(alpha-beta)

If cos (theta - alpha) = a, cos (theta - beta) = b , then the value of sin^(2) (alpha - beta) + 2ab cos (alpha - beta) is