Consider a cell composed of two cells:
(i). `Cu(s)Cu^(2+)(aq)` and (ii). `Ag(s)|Ag^(+)(aq)`
(b). The cell potential when `[Cu^(2+)]=2M` and `|Ag^(+)|=0.05M`
[Given: `C_(Cu^(2+)//Cu)^(@)=+0.344V,E_(Ag^(+)//Ag)^(@)=+0.80V]`

Calculate the emf of the cell Cu(s) | Cu^(2+) (aq) || Ag^(+)(aq) | Ag(s) Given, E_((Cu^(2+))//(Cu))=+ 0.34 V, E_((Ag^(+))//( Ag)) = 0.80 V

Calculate the emf of the following cell: Cu(s)|Cu^(2+) (aq)||Ag^(+) (aq)| Ag(s) Given that, E_(Cu^(2+)//Cu)^(@)=0.34 V, E_(Ag//Ag^(+))^(@)=-0.80 V

What is DeltaG^(@) for the following reaction Cu^(+2)(aq)+2Ag(s)rarrCu(s)+2Ag E_(Cu^(+2)//Cu)^(@)=0.34V E_(Ag^(+)//Ag)^(@)=0.8V

What is DeltaG^(@) for the following reaction Cu^(+2)(aq)+2Ag(s)rarrCu(s)+2Ag E_(Cu^(+2)//Cu)^(@)=0.34V E_(Ag^(+)//Ag)^(@)=0.8V

A cell is set up between copper and silver as follows : Cu(s)|Cu^(2+)(aq)||Ag^(+)(aq)|Ag(s) If two half cells work under standard conditions, calculate the emf of the cell. Given E_(Cu^(2+)|Cu)^(@)=0.34V,E_(Ag^(+)//Ag)^(@)=0.80V

E.M.F of the cell reaction , 2Ag^(+) + Cu to 2Ag + Cu^(2+) is 0.46 V . If E_(Cu^(2+) // Cu)^(0) is | 0.34 V , E_(Ag^(+)//Ag)^(0) is

For the galvanic cell, Cu|Cu^(2+)(0.13M)||Ag^(+)(0.01M)|Ag (ii) Is the cell reaction spontaneous ? ["Given : "E_(Cu^(2+)|Cu)^(@)=+0.34V and E_(Ag^(+)|Ag)^(@)=+0.80V] .