Home
Class 12
PHYSICS
Three containes of the same volume conta...

Three containes of the same volume contain three different gases. The masses of the molecules are `m_(1), m_(2)` and `m_(3)` and the number of molecules in their respective containers are `N_(1), N_(2)` and `N_(3)`. The gas pressure in the containers are `P_(1), P_(2)` and `P_(3)` respectively. All the gases are now mixed and put in one of the containers. The pressure `P` of mixture will be

A

`P lt (P_(1) + P_(2) + P_(3))`

B

`P = (P_(1) + P_(2) + P_(3))/(3)`

C

`P = P_(1) + P_(2) + P_(3)`

D

`P gt (P_(1) + P_(2) + P_(3))`

Text Solution

Verified by Experts

The correct Answer is:
c
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    NEET PREVIOUS YEAR (YEARWISE + CHAPTERWISE)|Exercise Gravitation|50 Videos
  • LAWS OF MOTION

    NEET PREVIOUS YEAR (YEARWISE + CHAPTERWISE)|Exercise Physics|60 Videos

Similar Questions

Explore conceptually related problems

Two perfect gases at absolute temperature T_(1) and T_(2) are mixed. There is no loss of energy. The masses of the molecules are m_(1) and m_(2) . The number of molecules in the gases are n_(1) and n_(2) . The temperature of the mixture is

Three perfect gases at absolute temperature T_(1), T_(2) and T_(3) are mixed. The masses f molecules are m_(1), m_(2) and m_(3) and the number of molecules are n_(1), n_(2) and n_(3) respectively. Assuming no loss of energy, the final temperature of the mixture is

If N_(1), N_(2), N_(3) ………Are the number of molecules with molecular masses M_(1), M_(2), M_(3) …….respectively, then average molecular mass is expressed as

If three unreactive gases having partial pressures , P_(A) , P_(B) and P_(C) and their moles are 1 , 2 and 3 respectively then their total pressure will be

The ratio of pressure of the same gas in two containers in (n_(1) T_(1))/(n_(2) T_(2)) where n_(1) & n_(2) are the number of moles and T_(1) & T_(2) are respective temperatures. If the containers are now joined find the ratio of pressure to the pressure :

NEET PREVIOUS YEAR (YEARWISE + CHAPTERWISE)-HEAT AND THERMODYNAMICS-PHYSICS
  1. The number of translational degree of freedom for a diatomic gas is

    Text Solution

    |

  2. Which of the following is not thermodynamical function

    Text Solution

    |

  3. Mercury thermometers can be used to measure temperatures upto

    Text Solution

    |

  4. If for a gas, (R)/(CV)=0.67, the gas is

    Text Solution

    |

  5. A thermodynamic system is taken from state A to B along ACB and is bro...

    Text Solution

    |

  6. A thermodynamic process is shown in the figure. The pressure and volum...

    Text Solution

    |

  7. Relation between pressure (p) and energy (E) of a gas is

    Text Solution

    |

  8. Three containes of the same volume contain three different gases. The ...

    Text Solution

    |

  9. For hydrogen gas C(P)-C(V)=alpha and for Oxygen gas C(P)-C(V)=b, where...

    Text Solution

    |

  10. One mole of an ideal monoatomic gas requires 207 J heat to raise the t...

    Text Solution

    |

  11. According to the kinetic theory of gases, at absolute temperature

    Text Solution

    |

  12. The thermal capacity of 40 g of aluminium (specific heat =0.2 cal//gm^...

    Text Solution

    |

  13. A centigrade and a Fehrenheit thermometer are dipped in boiling water....

    Text Solution

    |

  14. For a certain gas the ratio of specific heats is given to be gamma = 1...

    Text Solution

    |

  15. 300K a gas (gamma = 5//3) is compressed adiabatically so that its pres...

    Text Solution

    |

  16. At constant volume, temperature is increased. Then

    Text Solution

    |

  17. A polyatomic gas with (n) degress of freedom has a mean energy per mol...

    Text Solution

    |

  18. Two containers A and B are partly filled with water and closed. The vo...

    Text Solution

    |

  19. The first law of thermodynamics is based on the law of conservation of

    Text Solution

    |

  20. 10 gm of ice cubes at 0^(@)"C" are released in a tumbler (water equi...

    Text Solution

    |