निम्नलिखित समीकरणों को हल कीजिए :
`cos theta -cos 2 theta = sin 3 theta `

( cos 3 theta - sin 3 theta )/( cos theta+ sin theta ) =

( sin 3 theta )/( sin theta ) -(cos 3 theta )/( cos theta )=

If 2-cos^(2)theta = 3 sin theta cos theta then theta =

2 cos theta - cos 3 theta - cos 5 theta - 16 cos^(3) theta sin^(2) theta =

1 + (cos 2 theta + cos 6 theta)/(cos 4 theta) = (sin 3 theta)/(sin theta).

Prove that ( cos theta + cos 2 theta + cos 3 theta + cos 4 theta)/(sin theta + sin 2 theta + sin 3 theta + sin 4 theta)= cot ""(5theta)/(2).

cos (2 theta) cos ((theta) / (2)) - cos (3 theta) cos ((9 theta) / (2)) = sin (5 theta) sin ((5 theta) / (2))

( sin theta - 2 sin ^ 3 theta ) / (2 cos ^ 3 theta - cos theta ) = tan theta

(sin3 theta+cos3 theta)/(cos theta-sin theta)=1+2xx sin2 theta

(cos theta + sin theta )/( cos theta - sin theta )-(cos theta - sin theta )/( cos theta + sin theta ) =