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In Figure, if A C is bisector fo /B A D ...

In Figure, if `A C` is bisector fo `/_B A D` such that `A B=3\ c m\ a n d\ A C=5\ c m ,` then `C D=` `2\ c m` (b) `3\ c m` (c) `4\ c m` (d) `5\ c m`

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