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नीचे दिए गए मानक इलेक्ट्रोड विभवों के आध...

नीचे दिए गए मानक इलेक्ट्रोड विभवों के आधार पर धातुओं को उनकी बढ़ती हुई अपचायक क्षमता के क्रम में व्यवस्थित कीजिये ।
`K^(+)//K=-2.93V , Ag^(+)//Ag=0.80V`,
`Hg^(2+)//Hg=0.79V`
`Mg^(2+)//Mg=-2.37 V, Cr^(3+)//Cr=-0.74V`

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Given the standard electrode potentials K^(+)|K=-2.93V,Ag^(+)|Ag=0.80V,Hg^(2+)|Hg=0.79V Mg^(2+)|Mg=-2.37V,Cr^(3+|Cr=-0.74V The metal having highest reducing power is

Given : K^(+)|K=-2.79V, Ag^(+)|Ag=0.80V, Hg^(2+)|Hg=0.79V, Mg^(2+)|Mg=-2.37V and Cr^(3+)|Cr=-0.74V . Arrange these metals in their increasing order of reducing power.

Given the standard electrode potentials K^+//K= -2.93V, Ag^+//Ag = +0.8V, Hg^(2+)//Hg= 0.79 V, Mg^(2+)//Mg = -2.36V Cr^(3+)//Cr = 0.74 V Arrange them in increasing order of reducing power.