A current in a circuit having constant resistance is tripled. How does this affect the power dissipation?

In the series LCR circuit, the power dissipation is through

Keeping the potential difference constant, the resistance of a circuit is halved. How does the current change?

In the series LCR circuit , the power dissipation is through

In a series LCR circuit connected to an ac source of voltage v=v_msinomegat , use phasor diagram to derive an expression for the current in the circuit. Hence obtain the expression for the power dissipated in the circuit.Show that power dissipated at resonance is maximum.

If V_0 and I_0 are the peak current and voltge across the resistor in a series L-C-R circuit, then the power dissipated in the circuit is (power factor =costheta)

If V_0 and I_0 are the peak current and voltge across the resistor in a series L-C-R circuit, then the power dissipated in the circuit is (power factor =costheta)

A sinusoidal ac current flows through a resistor of resistance R . If the peak current is I_(p) , then the power dissipated is