The equation `[1 2 2 1 3 4 2 4k][x y z]=[0 0 0]` has `a` solution for `(x ,y ,z)` besides `(0,0,0)dot` Then the value of `k` is _______.

The equation [[1, 2 ,2 ],[1 ,3, 4],[ 2, 4,k]][[x ,y, z]] =[[0,0, 0]] has a solution for (x ,y ,z) besides (0,0,0)dot Then the value of k is _______.

The equation [[1, 2 ,2 ],[1 ,3, 4],[ 2, 4,k]][(x) ,(y), (z)] =[(0),(0), (0)] has a solution for (x ,y ,z) besides (0,0,0)dot Then the value of k is _______.

The equation [(1,2,2),(1,3,4),(3,4,k)]=[(0),(0),(0)] has a solution for (x, y, z) besides (0, 0, 0). Then the value of k is _________ .

The equation [(1,2,2),(1,3,4),(3,4,k)]=[(0),(0),(0)] has a solution for (x, y, z) besides (0, 0, 0). Then the value of k is _________ .

If the system of equation : x + y + z = 0 , 2 x + 3y + 4z = 0 , kx + y - z = 0 has a non - zero solution , then the value of k is

The equation 2x+y-4z=0, x-2y+3z=0 , x-y+z=0 have

The equations x+y-2z=0,2x-3y-z=0,x-5y+4z=k have non-zero solutions if k=

If the system of equation 14x-3y+z=12, x-2y=0 and x+2z=0 has a solution (x_(0), y_(0), z_(0)) , then the value of x_(0)^(2)+y_(2)^(2)+z_(2)^(2) is equal to

If the system of equation 14x-3y+z=12, x-2y=0 and x+2z=0 has a solution (x_(0), y_(0), z_(0)) , then the value of x_(0)^(2)+y_(2)^(2)+z_(2)^(2) is equal to