In a triangle ABC with fixed base BC, the verte moves such that `cos B+cosC =4sin^2(A/2)` then

In a triangle ABC with fixed base BC,the verte moves such that cos B+cos C=4sin^(2)((A)/(2)) then

In a triangle ABC with fixed base BC, the vertex A moves such that cos B+cosC=4sin^(2)A/2 . If a,b,c denote the lengths of the triangle opposite to the angles A,B and C respectively, then

In a triangle ABC with fixed base BC, the vertex A moves such that cos B + cos C = 4sin A//2 . If a, b, and c denote the lengths of the sides of the triangle opposite to the angles A, B, and C, respectively, then

In a triangle ABC with fixed base BC, the vertex A moves such that cos B + cos C = 4 sin^(2) A//2 If a, b and c denote the lengths of the sides of the triangle opposite to the angles A,B and C respectively, then

In a triangle ABC with fixed base BC, the vertex A moves such that cos B + cos C = 4 sin^(2) A//2 If a, b and c denote the lengths of the sides of the triangle opposite to the angles A,B and C respectively, then

a triangle ABC with fixed base BC, the vertex A moves such that cos B+cos C=4sin^(2)(A)/(2). If a,b and c, denote the length of the sides of the triangle opposite to the angles A,B, and C, respectively,then b+c=4a(b)b+c=2a the locus of point A is an ellipse the locus of point A is a pair of straight lines

In Delta ABC prove that a(cosB + cosC) = 2(b+c) sin^2(A/2)

In a triangle ABC,sin A-cos B=cosC,then angle B is

Base BC of triangle ABC is fixed and opposite vertex A moves in such a way that tan.(B)/(2)tan.(C)/(2) is constant. Prove that locus of vertex A is ellipse.