E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that `DeltaA B E ~ DeltaC F B`.

Explanation

To show that triangle ABE is similar to triangle CFB, we will use the Angle-Angle (AA) similarity criterion. Here’s a step-by-step solution:

### Step 1: Identify the triangles
We have two triangles to consider: triangle ABE and triangle CFB.

### Step 2: Identify the angles in triangle ABE
- Angle BAE (∠BAE) is one angle in triangle ABE.
- Angle AEB (∠AEB) is another angle in triangle ABE.
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