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In figure ABC and AMP are two right tri...

In figure ABC and AMP are two right triangles, right angles at B and M respectively. Prove that(i) `DeltaA B C~ DeltaA M P` (ii) `(C A)/(P A)=(B C)/(M P)`

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(i)In `Delta ABC` and `Delta AMP`
`/_BAC = /_PAM`, As both angles are common.
`/_ABC =/_AMP = 90^@`
As these two angles are equal, third angle will also be equal for these two triangles.
As, all three angles are equal, we can say that
`Delta ABC ~ Delta AMP`
(ii)It also means,
`(AB)/(AM) = (CA)/(PA) = (BC)/(MP)`
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