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(sin A+ sin 3A +sin 5 A+ sin 7A)/ ( cos ...

` (sin A+ sin 3A +sin 5 A+ sin 7A)/ ( cos A + cos 3A +cos 5A+ cos 7A)=tan 4A`

Answer

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( sin A + sin 3A + sin 5A + sin 7A)/(cos A + cos 3 A + cos 5 A + cos 7A) = tan 4A.

(sinA + sin3A) / (cosA + cos3A) = tanalpha, (cosA-cos2A) / (sinA + sin2A) = tanbeta, (sinA + sin3A + sin5A + sin7A) / (cosA + cos3A + cos5A + cos7A) = tan gamma , (cosA-cos5A-cos9A + cos13A) / (sinA-sin5A + sin9A-sin13A) = tandelta, then (a) alpha = 4beta (b) gamma = 2alpha (c) gamma = delta (d) none

Knowledge Check

  • ( sin 4 A sin 3A - sin 5A sin 2A+ sin 7A sin 4A )/(cos 2A cos 3A - cos 2A * cos 7A + cos A * cos 10A )=

    A
    `tan4 A * tan 5A `
    B
    `tan 5A * tan 6A `
    C
    `tan 4A * tan 6A `
    D
    `tan 5A * tan 2A `

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