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" of "int(0)^(1)x(1-x)^(99)dx" is "...

" of "int_(0)^(1)x(1-x)^(99)dx" is "

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int_(0)^(1) x dx

int_(0)^(1) x dx

what is the value of int_0^(1) x(1-x)^99 dx ?

Evaluate : (i) int_(0)^(1)x(1-x)^(n)dx (ii) int_(0)^(1)x(1-x)^(3//2)dx

int_(0)^(1)(x)/(x+1)dx=

int_(0)^(1)(1)/(1+x)dx=

int_(0)^(1)x e^(x)dx=

int_(0)^(1)x(1-x)^(4)dx=(1)/(30)

The value of int_(0)^(2pi)cos^(99)x dx is