f(x)={[(k cos x)/(pi-2x),,quad x<(pi)/(2)],[3,,quad x=(pi)/(2)],[(3tan2x)/(2x-pi),,quad x>(pi)/(2)]

f(x),={(k cos x)/(pi-2x),quad if x!=(pi)/(2) and 3,quad if x=(pi)/(2) at x,=(pi)/(2)

Find the values of k so that the function fis continuous at the indicated point in f(x)={((k cos x)/(pi-2x),quad if x!=(pi)/(2)),(3 if x=(pi)/(2)) at x=(pi)/(2)

For f(x)=(k cos x)/(pi-2x), if x!=(pi)/(2),3, if x=(pi)/(2) then find the value of k so that f is continous at x=(pi)/(2)

Find k if the function is continuous at x=(pi)/(2) if (a) f(x)={{:((k cos x )/(pi-2x),x ne (pi)/(2)),(3,if x=(pi)/(2)):} at x=(pi)/(2) (b) f(x)={{:(kx+1, if x le 2),(cos x,if x gt 2):} at x=2 (c ) if f(x)={{:(k^(2)x-k,if x le 1),(2 , if x lt 1):} is continous on R then find the value (s) of k

Let f(x)=(k cos x)/(pi-2x) if x!=(pi)/(2) and f(x=(pi)/(2)) if x=(pi)/(2) then find the value of k if lim_(x rarr(pi)/(2))f(x)=f((pi)/(2))

Determine the value of k, if f(x) = {((kcosx)/(pi-2x),if x!=(pi)/2),(3,if x = (pi)/2):}

Let f(x)={:{((kcosx)/(pi-2x)',xne(pi)/(2)),(3",",x=(pi)/(2).):} If lim_(xto(pi)/(2))f(x)=f((pi)/(2)), find the value of k.

Let f(x)={:{((kcosx)/(pi-2x)',xne(pi)/(2)),(3",",x=(pi)/(2).):} If lim_(xrarr(pi)/(2))f(x)=f((pi)/(2)), find the value of k.

Find the value of k so that the function f is continuous at x=pi//2,f(x)={:{((kcosx)/(pi-2x)", if "x!=(pi)/(2)),(5", if "x=(pi)/(2)):}

Find the values of k so that the function f is continuous at the indicated point f(x) = {((k cos x)/(pi-2x)",","if" x ne (pi)/(2)),(3,"if" x= (pi)/(2)):} " at " x= (pi)/(2)