The velocity and acceleration vectors of a particle undergoing circular motion are `v = 2 hat(i) m//s and a = 2 hat(i)+4 hat(j)m//s^(2)` respectively at some instant of time. The radius of the circle is

Velocity and acceleration of a particle at time t = 0 are u=(2hat(i)+3hat(j))m//s and a=(4hat(i)+2hat(j))m//s^(2) respectively. Find the velocity and displacement of particle at t = 2 s.

Assertion: Velocity and acceleration of a particle in circular motion at some instant are: v=(2hat(i))ms^(-1) and a=(-hat(i)+2hat(j))ms^(-2) , then radius of circle is 2m . Reason: Speed of particle is decreasing at a rate of 1ms^(-2) .

Assertion: Velocity and acceleration of a particle in circular motion at some instant are: v=(2hat(i))ms^(-1) and a=(-hat(i)+2hat(j))ms^(-2) , then radius of circle is 2m . Reason: Speed of particle is decreasing at a rate of 1ms^(-2) .

At a particular instant velocity and acceleration of a particle are (-hat(i)+hat(j)+2hat(k))m//s and (3hat(i)-hat(j)+hat(k))m//s^(2) respectively at the given instant particle's speed is :

At a particular instant velocity and acceleration of a particle are (-hat(i)+hat(j)+2hat(k))m//s and (3hat(i)-hat(j)+hat(k))m//s^(2) respectively at the given instant particle's speed is :

Velocity and acceleration vectors of a charged particle moving in a magnetic field at some instant are vec(v)=3hat(i)+4hat(j) and vec(a)=2hat(i)+xhat(j) . Selcet the wrong alternative.

Velocity and acceleration vectors of charged particle moving perpendicular to the direction of magnetic field at a given instant of time are vartheta= 2hat(i) + c hat(j) and bar(a) = 3 hat(i) + 4 hat(j) respectively. Then the value of .c. is

Velocity and acceleration vectors of charged particle moving perpendicular to the direction of magnetic field at a given instant of time are vartheta= 2hat(i) + c hat(j) and bar(a) = 3 hat(i) + 4 hat(j) respectively. Then the value of .c. is