An `alpha`-particle is accelerated through a.p.d of `10^(6)` volt the `K.E.` of particle will be

An alpha particle is acceleration through a potential difference of 10^(6) volt. Its kinetic energy will be

A protons , a deuteron and an alpha-particle are accelerated through the same p.d of V volt. The velocities acquired by them are in the ratio

An alpha partaicle is accelerated through a potential difference of 10^4 V . The gain in K.E. of the alpha particle is .

What is the de-Broglie wavelength of the alpha -particle accelerated through a potential difference of V volt ? (mass of alpha -particle = 6.6455 xx 10^(-27) kg)

An alpha-"particle" is accelerated through a potential difference of V volts from rest. The de-Broglie's wavelengths associated with it is.

An alpha-"particle" is accelerated through a potential difference of V volts from rest. The de-Broglie's wavelengths associated with it is.

An alpha-"particle" is accelerated through a potential difference of V volts from rest. The de-Broglie's wavelengths associated with it is.

When an alpha-particle is acceleration by a PD of 3 volt, its energy is